Free Online ATI TEAS Test Practice with Answers 12

When preparing for the ATI TEAS test, engaging in thorough online simulated practice is one of the keys to success. By participating in free ATI TEAS online practice tests, examinees can familiarize themselves with the exam’s format, content, and time constraints, thereby better preparing and strategizing for the test. We will provide you with a carefully prepared set of free ATI TEAS online practice tests, aimed at helping you assess your preparedness and adequately ready yourself for the exam.

Math

1. An event coordinator has a budget of $680. If she spent $75 on balloons and $65 on invitations, what percent of her budget does she have left?

A. 79.4%
B. 20.6%
C. 9.6%
D. 86.7%

Correct Answer: A

Answer Explanation:

Step 1: Calculate part (non-100%).
The first step is to identify the amounts needed to be added together to calculate the portion of the budget that has already been spent, which represents the part (non-100%).
75 + 65 = 140
Making 140 the part (non-100%).
Step 2: Divide the part (non-100%) by the whole (100%).
In order to find the percentage, we have to divide the part of the total available amount by the total amount available.
140 ÷ 680 = 0.2058823529
We can round this off to the third-place value. Check your answer choices to see if numbers were rounded to a different place value.
0.2058823529 → 0.206
Step 3: Multiply by 100.
Now that we have our decimal, we have to turn it into a percent.
0.206 × 100 = 20.6%
This tells us how much of the budget has already been spent. Finally, we have to find the percentage of what she has left.
Step 4: Subtract budget spent from total budget.
The event coordinator spent 20.6% of her budget. In order to find the percentage that is left we will subtract the percentage she spent from 100%.
100% – 20.6% = 79.4%
The event coordinator has 79.4% of her budget left.

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2. Jessica is wrapping a gift in a rectangular box with gift wrapping paper for a birthday party. The box is 11 inches long, 8 inches wide, and 5 inches tall. How much gift wrapping paper will she need to wrap the box?

A. 150 in²
B. 440 in²
C. 183 in²
D. 366 in²

Correct Answer: D

Answer Explanation:

Step 1: Interpret the problem.
We need to find the surface area of the box.
Step 2: Break your shape down into its net.
When we break down a rectangular prism into its net, we have six rectangles, a top and a bottom, a front, and a back, and two sides.

Ati teas12 3

Step 3: Determine how to find the area of each part of the net.
Let’s first find the area of the top and the bottom rectangles of the prism.
length × width = area
The length of the top rectangle is 11 in and the width is 8 in.
11 in × 8 in = 88 in²
The area of the top and bottom rectangles are 88 in² each.
Now we find the area of the front and back rectangles.
The length of the front rectangle is 11 in and the width is 5 in.
11 in × 5 in = 55 in²
The area of the front and back rectangles are 55 in² each.
Lastly we find the area of the two side rectangles.
The length of a side rectangle is 8 in and the width is 5 in.
8 in × 5 in = 40 in²
The area of each of the side rectangles is 40 in².
Step 4: Add up the areas of each part of the net.
2 × top area + 2 × front area + 2 × side area = surface area
2 × 88 in² + 2 × 55 in² + 2 × 40 in²
(2 × 88 in²) + (2 × 55 in²) + (2 × 40 in²) = 366 in²
So, Jessica needs 366 in² of gift wrap paper

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3. Carrie buys a can of paint from the local hardware store. The radius of the paint can is 4 inches and it is 11 inches tall. If the paint can is only one-half full, what is the volume of paint inside it?

V = π × r² × h, Use 3.14 for π.

A. 376.8 in²
B. 276.32 in³
C. 216.9112 in²
D. 552.64 in³

Correct Answer: B

Answer Explanation:

Step 1: Interpret the problem.
We need to find the total volume of the paint can, and then divide it by 2.
Step 2: Substitute the numbers into the equation.
Volume = π × r² × h
3.14 × (4 in2) × 11 in
Step 3: Solve using the order of operations.
3.14 × (4 in)2 × 11 in
3.14 × 16 in² × 11 in = 552.64 in³
Step 4: Divide the volume by 2 to find the amount of paint.
552.64 in³ ÷ 2 = 276.32 in³
The volume of paint inside the can when it is one-half full is 276.32 in³.

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